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10 abril, 2020Dos títulos, muchos cuentos
13 abril, 2020Solución enigma matemático 20 : Mi sobrina Claudia
Si no tuviéramos en cuenta la parte que nos indica que mi sobrina es menor de edad había seis posibilidades (14,41), (25,52), (36,63), (47,74), (58,85) y (69,96), pero solo la pareja (14,41) cumple que mi sobrina sea menor de edad. Por lo tanto mi sobrina tiene 14 años y mi hermana 41 años.
Enigma matemático 21 : La pirámide numérica
Os propongo un juego de jerarquía de operaciones. Tenéis que completar los huecos con operaciones de suma, resta, multiplicar o dividir, con paréntesis para obtener los resultados. Os ayudo con la última.
2 1 = 3
3 2 1 = 3
4 3 2 1 = 3
5 4 3 2 1 = 3
6 5 4 3 2 1 = 3
7 6 5 4 3 2 1 = 3
8 7 6 5 4 3 2 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
92 Comments
1+2=3
3x(2-1)=3
4-3+2:1=3
5-4+3-2+1=3
7-6-5-4+3x(2-1)=3
8-7-6-5+4-3+2x(1)=3
Seria así:
2 + 1 = 3
3 · (2 – 1) = 3
(4 – 3 ) · 2 + 1 = 3
5 – 4 + 3 – 2 + 1 = 3
6 – 5 + 4 – 3 + 2 – 1 = 3
7 – 6 + 5 – 4 + 3 – 2 · 1 = 3
8 – 7 + 6 – 5 – 4 + 3 + 2 · 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2 + 1 = 3
3 x ( 2 – 1) = 3
4 – 3 + 2 x 1 = 3
5 + 4 – 3 – 2 – 1 = 3
6 + 5 – 4 – 3 – 2 + 1 = 3
7 + 6 – 5 – 4 – 3 + 2 x 1 = 3
8 + 7 + 6 – 5 – 4 : 3 – 2 + 1 = 3
2+1=3
3x(2-1)=3
(4-3)x2+1=3
5-4+3-2+1=3
6+5-4-3-2+1=3
7-6+5-4+3-(2×1)
8-7+6-5-4+3+(2×1)
3x(2-1)
2 + 1 = 3
3 x (2 – 1) = 3
( 4 – 3) x (2 +1) = 3
(5 – 4) x 3 ( 2 – 1) = 3
6 + 5 – 4 – 3 – 2 + 1 = 3
( 7 – 6 +5) – ( -4 + 3 x 2 + 1) = 3
– 8 + 7 – 6 + 5 + 4 + 3 – 4 ( 2 x 1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1
3x(2-1)
4-3+(2×1)
5-4+3-2+1
6-5+4-3+2-1
7-6+5-4+3-(2×1)
8-7+6-5-4+3+(2×1)
2 + 1 = 3
3 2 1 = 3
4 – (3 x 2) + 1 = 3
(5 + 4 ) – ( 3 + 2 ) – 1 = 3
(6 + 5) – (4 + 3 ) – 2 + 1 = 3
(7 – 6) + 5 – 4 + 3 – ( 2 x 1) = 3
( 8 – 7) + 6 + 5 – 4 – 3 – ( 2 x 1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2 + 1 = 3
3 x (2 – 1) =3
4 -3 + 2 x 1= 3
5 – 4 +3 – 2 +1 = 3
6 + 5 – 4 – 3 – 2 +1= 3
7 -6 + 5 – 4 +3 – (2 x 1) = 3
8 +7 -6 -5 -4 +3 x (2 -1)=3
2+1 = 3
3 · (2 – 1) = 3
(4 – 3) · (2 + 1) = 3
(5 – 4)· 3 ·(2 – 1) = 3
(6 + 5 + 4) : (3 + 2) · 1 = 3
(7 – 6 +5 – 4 + 3) – (2 · 1) = 3
(8 – 7 + 6 – 5 + 4 + 3) : (2 + 1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3x(2-1)=3
4-3+2×1=3
5+4-3-2-1=3
6-5×4-3+2×1=3
7-6+5-4+3-2×1=3
8-7+6-5+4/3+2-1=3
2+1=3
3x(2-1)=3
(4-3)(2+1)=3
(5-4)x3x(2-1)=3
((6-5)x4-3)x(2+1)=3
(7-6)x(5-4)x3x(2-1)
(8-7)x(6-5)x(4-3)x(2+1)
Con esta jerarquía los complete yo:
2 + 1 = 3
3 : ( 2 – 1) = 3
( 4 – 3 + 2) : 1 = 3
5 + 4 – 3 – 2 – 1 = 3
6 – 5 + 4 – 3 + 2 – 1 = 3
7 – 6 + 5 – 4 + 3 – 2 : 1 = 3
8 – 7 + 6 – 5 – 4 + 3 + 2 : 1 = 3
2+1=3
3·(2-1)=3
4-3+(2/1)=3
5+4-3-2-1=3
((6+5+4)/3)-(2·1)=3
(7-6-5+4+3)·(2-1)=3
(8-7+6-5+4+3)/(2+1)=3
9-8+7-6+5-4-3+2+1=3
2+1=3
3(2-1)=3
(4-3)(2+1)=3
(5-4)•3•(2-1)=3
((6-5)•4-3)•(2+1)=3
(7-6)(5-4)•3•(2-1)=3
(8-7)(6-5)(4-3)(2+1)=3
La siguiente parte de la sucesión sería 10-9+8+7-6-5-4+3-2+1=3.
2 + 1 = 3
3 – 2 + 1 = 3
4 – 3 x 2 + 1 = 3
5 – 4 + 3 – 2 + 1 = 3
6 + 5 – 4 – 3 + 2+ 1 = 3
7 – 6 + 5 – 4- 3 + 2 + 1 = 3
8 + 7 – 6 – 5 + 4 – 3- 2 + 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3x (2-1)=3
(4-3) x 2+1=3
(5×4) : (3+2) -1=3
6- ((5×4) : (3+2)) +1=3
(7-6-5+4+3)x (2-1)=3
8-7-6+5-4+3-2+1=3
En la quinta operación lo primero seria un corchete y luego el paréntesis.
2+1=3
2•(2-1)=3
(4-3)•2+1=3
(5•4):(3+2)-1=3
6-[(5•4):(3+2)]+1=3
(7-6-5+4+3)•(2-1)=3
8-7-6+5-4+3-2+1=3
La pirámide numérica seria:
2+1=3
3· (2-1) = 3
4 – 3 + 2 · 1 = 3
5 + 4- 3 – 2 – 1 = 3
6 + 5 – 4 – 3 – 2 + 1 = 3
7 – 6 + 5 – 4 + 3 – 2 · 1= 3
8 – 7 + 6 + 5 – 4 – 3 – 2 · 1 = 3
9 – 8+ 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
La solución sería:
2+1=3
3·(2-1)=3
(4-3)·(2+1)=3
(5+4)-(3·2)·1=3
(6-5)-(4-3)+2+1=3
(7-6)+(5-4)+(3-2)·1=3
(8-7)-(6-5)+((4-3)+2)·1=3
2 + 1= 3
3 x (2 – 1)= 3
(4 – 3) x 2 + 1 = 3
(5 x 4) : (3 + 2) – 1 = 3
6 – [(5 x 4) : (3 + 2) +1 = 3
(7 – 6 – 5 + 4 + 3) x (2 – 1) = 3
8 – 7 – 6 + 5 – 4 + 3 – 2 – 1= 3
2 + 1 = 3
3 x (2 – 1) = 3
(4 – 3) + 2 x 1 = 3
(5 + 4 – 3) : 2 x 1 = 3
(6 – 5 + 4 + 3) : 2 – 1 = 3
(7 + 6 – 5) : 4 + 3 – 2 x 1 = 3
(8 + 7 – 6 + 5) – 4 x 3 + 2 – 1 = 3
2+1=3
3x(2-1)=3
(4-3)x2+1=3
(5×4):(3+2)-1=3
6-[(5×4):(3+2)]+1=3
(7-6-5+4+3)x(2-1)=3
8-7-6+5-4+3-2+1=3
2+1
3x(2-1)
4-3+2×1
(5+4):3x(2-1)
6-5+4-3+2-1
7-6-5+4+3x(2-1)
(8+7+6-5-4-3):(2+1)
2-1=3
3x(2-1)=3
4-3+2×1=3
5+4:3x(2-1)=3
6-5+4-3x(2-1)=3
7-6-5+4+3x(2-1)=3
(8+7+6-5-4-3):(2+1)=3
9-8+7-6+5-4-3+2+1=3
2+1
3x(2-1)
4-3+2×1
(5+4):3x(2-1)
6-5+4-3+2-1
7-6-5+4+3x(2-1)
(8+7+6-5-4-3):(2+1)
2 + 1 = 3
3 x (2 – 1) = 3
(4 – 3) x( 2 + 1) = 3
(5 + 4 – 3 ) : (2 x 1 ) = 3
(6 – 5) x ( 4 – 3) x ( 2 + 1) = 3
( 7 + 6 – 5 – 4 – 3) x ( 2 + 1) = 3
(8 – 7) x ( 6 – 5) x (4 – 3) x ( 2 + 1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3(2-1)=3
√4(3+2)+1=3
5+4-(3x2x1)=3
6-[(5×4):(3+2)]=3
(7×6):[(5×4)-3]-2+1=3
(8×7)-[(6+5)x4]-[3(2+1)=3
9-8+7-6+5-4-3+2+1=3
2 + 1 = 3
3 2 1 = 3
4 3 2 1 = 3
5 + 4 – 3 – 2 – 1 = 3
6 + 5 – 4 – 3 – 2 + 1 = 3
7 6 5 4 3 2 1 = 3
8 7 6 5 4 3 2 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3×(2-1)=3
(4-3)×(2+1)=3
(5-4)+3-2+1=3
(6-5)+4-3+2-1=3
7-6+(5-4)+3-2×1=3
(8-7)+(6-5)+4-3×(2-1)=3
2 x 1 = 3
3 x ( 2 – 1 )= 3
– 4 + ( 3 x 2 + 1 ) = 3
(5 + 4) – ( 3 x 2 x 1 ) = 3
– (6 + 5) + ( 4 x 3 + 2 x 1 ) = 3
( 7 – 6 ) x [( 5 + 4 ) – 3 – 2 ] -1 = 3
[ (8 + 7 + 6 – 5) ÷ 4 ] -3 + 2 x 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
8+7-6-5-4+3:(2-1)=3
SOLUCIÓN:
2 + 1 = 3
3 x (2 – 1) = 3
(4 – 3 + 2) x 1 = 3
5 – 4 + 3 – 2 + 1 = 3
6 – 5 + 4 – 3 + 2 – 1 = 3
(7 – 6 + 5 – 4 + 3 -2) x 1 = 3
(8 + 7 – 6 – 5 + 4 – 3 – 2) x 1 = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
3×(2-1)=3
(4-3)×(2+1)=3
(5+4)-(3×2)×1=3
(6+5)-(4×3)+(2×1)=3
7÷(6×5)-(4×3)+(2+1)=3
(8+7)-(6+5)-(4+3)×(2-1)=3
2 + 1 = 3
3 ÷(2 – 1) = 3
4 – 3 + 2 ÷ 1 = 3
5 – 4 + 3 – 2 + 1 = 3
6 – 5 + 4 – 3 + 2 – 1 = 3
7 – 6 + 5 – 4 + 3 – 2 ÷1 = 3
8 + 7 – 6 – 5 +4 – 3 – 2 ÷ 1 = 3
La pirámide completa sería:
2+1=3
3 x (2-1)=3
(4-3) x (2+1)=3
(5+4-3) : (2×1)=3
(6-5) x (4-3) x (2+1)=3
(7+6-5-4-3) x (2+1)=3
(8-7) x (6-59 x (4-3) x (2+1)=3
9-8+7-6+5-4-3+2+2=3
2+1=3
3·(2-1)=3
4-3+2:1=3
5+4-3-2-1=3
6+5-4-2+1=3
7-6+5-4+3-2·1=3
8+7-6-5+4-3-2·1=3
9-8+7-6+5-4-3+2+1=3
2+1=3
3·(2-1)=3
4-3+2:1=3
5+4-3-2-1=3
6+5-4-3-2+1=3
7-6+5-4+3-2-1=3
8+7-6-5+4-3-2·1=3
9-8+7-6+5-4-3+2+1=3
2+1= 3
3 × (2 – 1) =3
(4 – 3) × 2 + 1=3
(5×4) : ( 3+2) – 1=3
6-(5×4) : (3+2) +1 =3
(7-6-5+4+3) ×( 2-1 )=3
8-7-6+5-4+3-2-1 =3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
Sería así:
2+1=3
3:(2-1)=3
(4-3+2):1=3
5-4+3-2+1=3
6-5+4-3+2-1=3
(7-6+5-4+3-2)·1=3
(8-7+6-5+4-3):(2-1)=3
9-8+7-6+5-4-3+2+1=3
3:2:1=3
4-3-2+1=3
5-4-3+2-1=3
6+5-4-3-2+1=3
8-7+6-5-4-3+2:1=3
9-8+7-6-5-4-3+2+1=3
2+1=3
3(2-1) =3
4-3+2×1=3
5+4-3-2-1=3
6+5-4-3-2+1=3
7-6+5-4+3-2×1=3
8+7-6-5+4-3-2×1=3
2 + 1 = 3
3 ÷ (2 – 1) = 3
4 – 3 + 2 ÷ 1 = 3
5 – 4 + 3 – 2 + 1 = 3
(6 – 5 + 4 + 3) ÷ 2 – 1 = 3
(7 – 6 – 5 + 4 + 3) ÷ (2 – 1) = 3
(8 – 7 + 6 – 5 + 4 – 3) ÷ (2 – 1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3(2-1) =3
4-3+2×1=3
5-4+3-2+1=3
6-5+4-3+2-1=3
7-6+5-4+3-2×1=3
8-7+6-5-4-3+2×1=3
2 +1 = 3
3 • (2 – 1)= 3
4 – (3 – 2) • 1 = 3
5 – 4 + 3 – 2 + 1 = 3
6 – 5 + 4 – 3 + (2 – 1) = 3
7-6 +5 – 4 +3 – 2 • 1 = 3
8-7+6-5+4-3• (2 – 1) = 3
2+1=3
3*(2-1)= 3
(4-3)*2+1= 3
(5*4):(3+2)+1= 3
6-[(5*4):(3+2)]+1= 3
(7-6-5+4+3)*(2-1)= 3
(8-7-6+5-4+3 )*(2-1) = 3
9 – 8 + 7 – 6 + 5 – 4 – 3 + 2 + 1 = 3
2+1=3
3*(2-1)=3
4-3+2*1=3
5-4+3-2+1=3
6-5+4-3+2-1=3
7-6+5-4+3-2*1=3
8-7+6-5*4-3-2*1=3
2+1=3
3*(2-1)=3
4-3+2*1=3
5-4+3-2+1=3
6-5+4-3+2-1=3
7-6+5-4+3-2*1=3
8-7+6-5*4-3-2*1=3
Es 3 porque haciendo operaciones da eso.